Cabinet Tuning Basics: Box, Port and Fb
Cabinet tuning basics start with one resonance. In a reflex box the enclosed air is a spring and the air in the port is a mass; together they form a Helmholtz resonator at the tuning frequency, Fb. Box volume, port area and port length set it, and the driver's T/S parameters decide which combination works.
What happens around Fb
- At Fb the port supplies most of the output and cone excursion is at its minimum.
- Above Fb the cone radiates directly and the port contributes less.
- Below Fb the port unloads the cone. Excursion rises steeply and the driver can pass Xmax with far less power than it would in a sealed box.
A reflex box is a 4th-order high-pass system (24 dB/octave ultimate roll-off) against 2nd-order (12 dB/octave) for a sealed box, and it carries more group delay near tuning.
The formula
Fb = (c / 2π) × √(Sp / (Vb × Leff))
where c is the speed of sound (343 m/s), Sp the port area, Vb the net box volume and Leff the port's effective length. Rearranged for length: Leff = Sp × c² / (4π² × Fb² × Vb).
Worked example: 200 L net, 200 cm² of port, Fb = 35 Hz gives Leff = 0.02 × 343² / (4π² × 35² × 0.2) = 0.243 m. The physical port is shorter than Leff because air beyond each end moves with it (end correction, roughly 0.73 × port diameter for a round port with one flanged end). For a round port of this area, that brings the cut length to about 13 cm.
The three variables
- Port length: longer tunes lower. Fb scales with 1/√Leff, so halving Fb takes four times the length.
- Port area: at a fixed tuning, length scales directly with area. Double the area, double the length. An undersized port produces wind noise ("chuffing") at high level.
- Box volume: chosen from the driver's Vas, Qts and Fs for the alignment you want. With the same port, a larger box tunes lower; for the same tuning, it needs a shorter port.
A published reference point
B&C give a recommended reflex enclosure for their 18TBW100 (Fs 35 Hz, Qts 0.39, Vas 175 L): 200 L tuned to 32 Hz. That is the kind of figure a maker's model produces; your own driver's parameters will give different numbers.
To model a Wavemark WM1850/8, enter Fs 42.9 Hz, Qts 0.644, Vas 120.9 L, Sd 1244 cm² and Xmax 12 mm, then check excursion at the power you plan to use (rated 1800 W AES).
High-pass below tuning
Because the cone unloads below Fb, set a high-pass filter at or just below the tuning frequency. It is the most effective protection a reflex sub has against over-excursion. See Xmax and excursion and limiter settings for subs.
Model before you cut
WinISD (reflex) and Hornresp (horns and scoops) are free and take T/S parameters directly. Start with Thiele/Small parameters, or browse our speaker designs.
Sources: B&C Speakers published data for the 18TBW100 (8 Ω), checked October 2026; Wikipedia: Bass reflex; Wavemark WM1850/8 spec sheet. Helmholtz resonator relation: L. L. Beranek, Acoustics. Calculated values rounded.
Questions
How do you calculate the tuning frequency of a ported box?
Fb = (c / 2π) × √(Sp / (Vb × Leff)), where c is 343 m/s, Sp the port area, Vb the net box volume and Leff the effective port length including end correction. For 200 L with 200 cm² of port at 35 Hz, Leff is about 0.24 m.
Does a bigger port change the tuning?
Yes. At a fixed length, more area raises the tuning. To keep the same tuning, port length must grow in proportion to area. Larger ports reduce air velocity and port noise.
Why do reflex subs need a high-pass filter?
Below the tuning frequency the port unloads the cone, so excursion rises steeply and the driver can exceed Xmax at modest power. A high-pass filter at or just below Fb prevents this.
