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Matching an Amplifier to Your Subs

Matching an amplifier to your subs comes down to voltage. The amp sets the maximum voltage across the coil; the driver's continuous rating sets how much it can take for long periods. Size the amp for clean headroom above that rating, then let a limiter, not a small amp, decide what the driver actually gets.

Work in volts

P = V² / R, so a rating converts directly to a voltage at the nominal load. For an 1800 W, 8 Ω driver such as the WM1850/8:

Amp power at 8 ΩRatio to 1800 WMax output (V RMS)Headroom
1800 W1×120 V0 dB
2700 W1.5×147 V+1.8 dB
3600 W2×170 V+3 dB

An amp with headroom reproduces transients above the average level cleanly. Music has a crest factor, so a channel sitting at the driver's continuous rating on average needs a few dB of extra voltage on peaks. The extra watts on the amp's spec sheet are only safe if the limiter holds the long-term level down.

Why clipping heats coils

A clipped amp holds the output at its rail voltage for part of each cycle. In the limit a sine clips into a square wave at the same peak voltage, which carries twice the power: +3 dB of heat into the coil with no increase in peak level. Clipping also adds odd harmonics, which in a passive system land on the HF drivers. A small amp run into clipping can deliver more heat to a coil than a large amp run clean.

Read the amp spec properly

Set the limiter in volts

Set the DSP's RMS limiter threshold to the voltage of the driver's continuous rating (120 V for 1800 W at 8 Ω), converted to the DSP output level using the amp's gain. Put a high-pass filter in front so the cone is not driven below the box's working range, where excursion rises steeply. A peak limiter set to the amp's maximum output stops it clipping. See limiter settings for subs.

Wavemark drivers

The WM1850/8 is rated 1800 W AES / 3600 W peak at 8 Ω; the WM18X451 1800 W RMS / 3600 W max, 8 Ω or 4 Ω. Both take the same 120 V RMS continuous at 8 Ω, so one amp platform and one limiter setting covers either.

More on ratings: RMS vs program vs peak power.

Sources: P = V²/R; RMS of a square wave equals its peak, RMS of a sine is peak/√2. Wavemark WM1850/8 spec sheet and WM18X451 product data. Calculated values rounded.

Questions

How powerful should my amp be for an 1800 W sub?

Enough to deliver at least the driver's continuous rating cleanly at your load, with headroom for peaks: 1800 W at 8 ohms is 120 V RMS, 3600 W is 170 V and about 3 dB more. Use a limiter to keep the long-term level at the driver's rating.

Can an underpowered amp damage a speaker?

Yes, if it is driven into clipping. A hard-clipped sine approaches a square wave carrying up to twice the power at the same peak voltage, so the coil heats faster than the level suggests.

Where should I set my sub limiter?

Set the RMS limiter to the voltage of the driver's continuous rating at its load, for example 120 V RMS for 1800 W at 8 ohms, with a high-pass filter ahead of it.